Question:
A charged 30 μF capacitor is connected to a 27 mH inductor. What is the angular frequency of free oscillations of the circuit?
Solution:
Capacitance, C = 30μF = 30×10−6F
Inductance, L = 27 mH = 27 × 10−3 H
Angular frequency is given as:
$\omega_{r}=\frac{1}{\sqrt{L C}}$
$=\frac{1}{\sqrt{27 \times 10^{-3} \times 30 \times 10^{-6}}}=\frac{1}{9 \times 10^{-4}}=1.11 \times 10^{3} \mathrm{rad} / \mathrm{s}$
Hence, the angular frequency of free oscillations of the circuit is 1.11 × 103 rad/s.