Question:
A carrier wave with amplitude of $250 \mathrm{~V}$ is amplitude modulated by a sinusoidal base band signal of amplitude $150 \mathrm{~V}$. The ratio of minimum amplitude to maximum amplitude for the amplitude modulated wave is $50: \mathrm{x}$, then value of $x$ is ...........
Solution:
$A_{\max }=A_{C}+A_{m}=250+150=400$
$A_{\min }=A_{C}-A_{m}=250-150=100$
$\frac{A_{\min }}{A_{\max }}=\frac{100}{400}=\frac{1}{4}=\frac{50}{200}$
$x=200$
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