Question:
A carrier signal $\mathrm{C}(\mathrm{t})=25 \sin \left(2.512 \times 10^{10} \mathrm{t}\right)$ is amplitude modulated by a message signal $\mathrm{m}(\mathrm{t})=5 \sin \left(1.57 \times 10^{8} \mathrm{t}\right)$ and transmitted through an antenna. What will be the bandwidth of the modulated signal?
Correct Option: , 4
Solution:
(4)
Band width $=2 \mathrm{f}_{\mathrm{m}}$
$\omega_{\mathrm{m}}=1.57 \times 10^{8}=2 \pi \mathrm{f}_{\mathrm{m}}$
$\mathrm{BW}=2 \mathrm{f}_{\mathrm{m}}=\frac{10^{8}}{2} \mathrm{~Hz}=50 \mathrm{MHz}$