Question:
A Carnot engine operates between two reservoirs of temperatures $900 \mathrm{~K}$ and $300 \mathrm{~K}$. The engine performs 1200 $\mathrm{J}$ of work per cycle. The heat energy (in $\mathrm{J}$ ) delivered by the engine to the low temperature reservoir, in a cycle, is______
Solution:
(600.00) Given; $T_{1}=900 K, T_{2}=300 K, W=1200 J$
Using, $1-\frac{T_{2}}{T_{1}}=\frac{W}{Q_{1}}$
$\Rightarrow 1-\frac{300}{900}=\frac{1200}{Q_{1}}$
$\Rightarrow \frac{2}{3}=\frac{1200}{Q_{1}} \Rightarrow Q_{1}=1800$
Therefore heat energy delivered by the engine to the low temperature reservoir, $Q_{2}=Q_{1}-W=1800-1200$
$=600.00 \mathrm{~J}$