Question:
A car is moving at an average speed of $60 \frac{2}{5} \mathrm{~km} / \mathrm{hr}$. How much distance will it cover in $6 \frac{1}{4}$ hours?
Solution:
Speed $=60 \frac{2}{5} \mathrm{~km} / \mathrm{h}$
Time $=6 \frac{1}{4} \mathrm{~h}$
We know that
Speed $=\frac{\text { Distance }}{\text { Time }}$
$\Rightarrow$ Speed $\times$ Time $=$ Distance
$\Rightarrow$ Distance $=60 \frac{2}{5} \times 6 \frac{1}{4}$
$\Rightarrow$ Distance $=\frac{302}{5} \times \frac{25}{4}$
$\Rightarrow$ Distance $=377 \frac{1}{2} \mathrm{~km}$
Hence, the distance covered in $6 \frac{1}{4} \mathrm{~h}$ is $377 \frac{1}{2} \mathrm{~km}$.