Question:
A box of 1.00 m3 is filled with nitrogen at 1.50 atm at 300 K. The box has a hole of an area 0.010 mm2. How much time is required for the pressure to reduce by 0.10 atm, if the pressure outside is 1 atm?
Solution:
Volume of the box = 1 m3 = V1
Initial pressure P1 = 1.5 atm
Final pressure P2 = 1.4 atm
Air pressure Pa = 1 atm
Initial temperature T1 = 300 K
Final temperature T2 = 300 K
Area of the hole = 10-8 m2
Pressure difference between tyre and atmosphere = 1.5 – 1 atm
Mass of nitrogen = 46.5 × 10-27 kg
Using the above information, we can calculate the time required as τ = 1.34 × 105 sec