A body rotating with an angular speed of

Question:

A body rotating with an angular speed of $600 \mathrm{rpm}$ is uniformly accelerated to $1800 \mathrm{rpm}$ in $10 \mathrm{sec}$. The number of rotations made in the process is_________.

Solution:

$\omega_{f}=\omega_{0}+\alpha t$

$\alpha=1200 \times 6$

$\theta=\omega_{0} t+\frac{1}{2} \alpha t^{2}$

$=600 \times \frac{10}{60}+\frac{1}{2} \times 1200 \times 6 \times \frac{1}{36}$

$\theta=200$

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Naman
Aug. 4, 2022, 9:44 p.m.
Ye 1200 kese aa gya