Question.
A body is initially at rest. It undergoes one-dimensional motion with constant acceleration. The power delivered to it at time t is proportional to
(i) $t^{\frac{1}{2}}$
(ii) $t$
(iii) $t^{\frac{3}{2}}$
(iv) $t^{2}$
A body is initially at rest. It undergoes one-dimensional motion with constant acceleration. The power delivered to it at time t is proportional to
(i) $t^{\frac{1}{2}}$
(ii) $t$
(iii) $t^{\frac{3}{2}}$
(iv) $t^{2}$
solution:
Answer: (ii) t
Mass of the body = m
Acceleration of the body = a
Using Newton’s second law of motion, the force experienced by the body is given by the equation:
F = ma
Both m and a are constants. Hence, force F will also be a constant.
F = ma = Constant … (i)
For velocity v, acceleration is given as,
$a=\frac{d v}{d t}=$ Constant
$d v=$ Constant $\times d t$
$v=\alpha t$ $\ldots(i i)$
Where, $\alpha$ is another constant
$v \propto t$ $\ldots$ (iii)
Power is given by the relation:
P = F.v
Using equations (i) and (iii), we have:
$P \propto t$
Hence, power is directly proportional to time.
Answer: (ii) t
Mass of the body = m
Acceleration of the body = a
Using Newton’s second law of motion, the force experienced by the body is given by the equation:
F = ma
Both m and a are constants. Hence, force F will also be a constant.
F = ma = Constant … (i)
For velocity v, acceleration is given as,
$a=\frac{d v}{d t}=$ Constant
$d v=$ Constant $\times d t$
$v=\alpha t$ $\ldots(i i)$
Where, $\alpha$ is another constant
$v \propto t$ $\ldots$ (iii)
Power is given by the relation:
P = F.v
Using equations (i) and (iii), we have:
$P \propto t$
Hence, power is directly proportional to time.