8x-7-3x=6x-2x-3
Given, $\quad 8 x-7-3 x=6 x-2 x-3$
$\Rightarrow 8 x-3 x-6 x+2 x=-3+7$ [transposing $6 x,-2 x$ to LHS and $-7$ to RHS]
$\therefore$ $x=4$
Leave a comment
All Study Material
