Question:
8 taps of the same size fill a tank in 27 minutes. If two taps go out of order, how long would the remaining taps take to fill the tank?
Solution:
Let x min be the required number of time. Then, we have:
| No. of taps | 8 | 6 |
| Time (in min) | 27 |
Clearly, less number of taps will take more time to fill the tank .
So, it is a case of inverse proportion.
Now, $8 \times 27=6 \times x$
$\Rightarrow x=\frac{8 \times 27}{6}$
$\Rightarrow x=36$
Therefore, it will take 36 min to fill the tank.