Question:
6 cows can graze a field in 28 days. How long would 14 cows take to graze the same field?
Solution:
Let x be the number of days. Then, we have
| No. of days | 28 | x |
| No. of cows | 6 | 14 |
Clearly, more number of cows will take less number of days to graze the field.
So, it is a case of inverse proportion.
Now, $28 \times 6=x \times 14$
$\Rightarrow x=\frac{28 \times 6}{14}$
$\Rightarrow x=12$
Therefore, 14 cows will take 12 days to graze the field.