4 (3p + 2) – 5 (6p – 1) = 2 (p – 8) – 6 (7p – 4)

Given,     $4(3 p+2)-5(6 p-1)=2(p-8)-6(7 p-4)$

$\Rightarrow$ $12 p+8-30 p+5=2 p-16-42 p+24$

$\Rightarrow \quad-18 p+13=-40 p+8$

$\Rightarrow$ $-18 p+40 p=8-13 \quad$ [transposing $-40 p$ to LHS and 13 to RHS ]

$\Rightarrow \quad 22 p=-5$ 

$\Rightarrow \quad \frac{22 p}{22}=\frac{-5}{22}$ [dividing both sides by 22]

$\therefore$ $p=\frac{-5}{22}$