2 NO(g) + Cl2(g) ⇌ 2 NOCl (s) This reaction was studied at

Question:

$2 \mathrm{NO}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NOCl}(\mathrm{s})$

This reaction was studied at $-10^{\circ} \mathrm{C}$ and the following data was obtained

$[\mathrm{NO}]_{0}$ and $\left[\mathrm{Cl}_{2}\right]_{0}$ are the initial concentrations and $\mathrm{r}_{0}$ is the initial reaction rate.

The overall order of the reaction is______. (Round off to the Nearest Integer).

Solution:

$\mathrm{r}=\mathrm{k}[\mathrm{NO}]^{\mathrm{m}}\left[\mathrm{Cl}_{2}\right]^{\mathrm{n}}$

$=\mathrm{k}(0.1)^{\mathrm{m}}(0.1)^{\mathrm{n}}$ ...............(1)

$=\mathrm{k}(0.1)^{\mathrm{m}}(0.2)^{\mathrm{n}}$ ...............(2)

$=\mathrm{k}(0.2)^{\mathrm{m}}(0.2)^{\mathrm{n}}$ ...............(3)

$n=1$

$\mathrm{m}=2$

$\mathrm{m}+\mathrm{n}=3$

Leave a comment