2.2 cubic dm of brass is to be drawn into a cylindrical

The brass volume that has to be drawn into a cylindrical wire is given is $2.2 \mathrm{dm}^{3}=2.2 \times 10^{-3} \mathrm{~m}^{3}$

We have to make a cylindrical wire out of it with diameter =0.25 cm

So the radius of this wire $0.125 \times 10^{-2} \mathrm{~m}$

We have to find the length of this wire.

Let the length of this wire be 

We know that the volume of a cylinder $=\pi r^{2} h$.

We know, the volume of the cylinder should be equal to the volume of the given brass

$\Rightarrow \pi\left(0.125 \times 10^{-2}\right)^{2} \times h=2.2 \times 10^{-3}$

$h=\frac{22 \times 10^{-3} \times 10^{4}}{\pi \times .125 \times .125}$

$=\frac{4 \times 7}{.25 \times .25}$

$=448$

Therefore, h = 448 m

Hence, the length of the cylindrical wire that can be formed is 448 m