Question: 10x-5-7x=5x+15-8
Solution:
Given, $10 x-5-7 x=5 x+15-8$
$\Rightarrow \quad 10 x-7 x-5 x=5+15-8$ [transposing $5 x$ to LHS and $-5$ to RHS]
$\Rightarrow \quad-2 x=12$
$\Rightarrow \quad \frac{-2 x}{-2}=\frac{12}{-2}$ [dividing both sides by -2]
$\therefore \quad x=-6$
