1 kg of ice at 0°C is mixed with 1 kg of steam at 100°C.

Question:

$1 \mathrm{~kg}$ of ice at $0^{\circ} \mathrm{C}$ is mixed with $1 \mathrm{~kg}$ of steam at $100^{\circ} \mathrm{C}$. What will be the composition of the systemwhen thermal equilibrium is reached? Latent heat of fusion of ice=3.36 $\times 10^{5} \mathrm{~J} / \mathrm{kg}$ and latent heat of vaporization of water $=2.26 \times 10^{6} \mathrm{~J} / \mathrm{kg}$.

Solution:

Leave a comment

Close

Click here to get exam-ready with eSaral

For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.

Download Now