Question:
$0.27 \mathrm{~g}$ of a long chain fatty acid was dissolved in $100 \mathrm{~cm}^{3}$ of hexane. $10 \mathrm{~mL}$ of this solution was added dropwise to the surface of water in a round watch glass. Hexane evaporates and a monolayer is formed. The distance from edge to centre of the watch glass is $10 \mathrm{~cm}$. What is the height of the monolayer?
$\left[\right.$ Density of fatty acid $\left.=0.9 \mathrm{~g} \mathrm{~cm}^{-3}, \pi=3\right]$
Correct Option: , 2
Solution:
