0.25(4x-5)=0.75x +8

Given, $0.25(4 x-5)=0.75 x+8$

$\Rightarrow \quad x-1.25=0.75 x+8$

$\Rightarrow$ $x-0.75 x=1.25+8$ [transposing $0.75 x$ to LHS and $1.25$ to RHS]

$\Rightarrow$ $0.25 x=9.25$

$\Rightarrow$ $\frac{0.25 x}{0.25}=\frac{9.25}{0.25}$ [dividing both sides by $0.25$ ]

$\therefore$ $x=37$